1.) Using Ohm's law, explain how voltage changes in relation to current, assuming that resistance remains constant.

2.) As the electric current in a lightbulb is slowly increased the filament glows more and more brightly. Why does this happen?

3.) Why did some of the lightbulb's you tried burn out?

4.) Why is there zero current when a lightbulb burns out?

Question

Lauren Montoya

Physics

17 July, 17:28

1.) Using Ohm's law, explain how voltage changes in relation to current, assuming that resistance remains constant.

2.) As the electric current in a lightbulb is slowly increased the filament glows more and more brightly. Why does this happen?

3.) Why did some of the lightbulb's you tried burn out?

4.) Why is there zero current when a lightbulb burns out?

+4

Answers (1)

Know the Answer?

Leilani Ritter · Answer 1

1.) Ohm's law is understood as I = V/R. Given that resistance is constant, then voltage changes directly proportional to current.

2.) The more current that passes through a lightbulb, the brighter it glows. The higher the current, the higher the power, where power determines the brightness of a bulb.

3.) A bulb has a specific limit to how much power (Watts) it can handle. Going over the limit would cause the bulb to burn out.

4.) When a bulb burns out, no current will be able to pass through the filament.