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10 November, 16:49

First, you will investigate purely vertical motion. The kinematics equation for vertical motion (ignoring air resistance) is given byy (t) = y0+v0t - (1/2) gt2, where y0=0 is the initial position, v0 is the initial speed, and g is the acceleration due to gravity. Drag the cannon downwards so it is at ground level, or 0 m (which represents the initial height of the object), then fire the pumpkin straight upward (at an angle of 90∘) with an initial speed of 14 m/s. How long does it take for the pumpkin to hit the ground?

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  1. 10 November, 16:55
    0
    2.85 s.

    Explanation:

    y (t) = y (0) + v₀t + 1/2 gt²

    y (t) is vertical displacement, y (0) is initial position, v₀ is initial velocity and t is time required to make vertical displacement and g is acceleration due to gravity.

    Here y (0) is zero, v₀ = 14 m/s, g = 9.8 m s⁻², y (t) = 0, as the pumpkin after time t comes back to its initial position, that is ground.

    We shall take v₀ as negative as it is in upward direction and g as positive as it acts in downward direction

    Put the values in the equation above,

    0 = 0 - 14t + 1/2 x 9.8 t²

    14 t = 1/2 x 9.8 t²

    t = 28 / 9.8

    t = 2.85 s.
  2. 10 November, 17:02
    0
    2.85 s.

    Explanation:

    y (t) = y (0) + v₀t + 1/2 gt²

    y (t) is vertical displacement, y (0) is initial position, v₀ is initial velocity and t is time required to make vertical displacement and g is acceleration due to gravity.

    Here y (0) is zero, v₀ = 14 m/s, g = 9.8 m s⁻², y (t) = 0, as the pumpkin after time t comes back to its initial position, that is ground.

    We shall take v₀ as negative as it is in upward direction and g as positive as it acts in downward direction

    Put the values in the equation above,

    0 = 0 - 14t + 1/2 x 9.8 t²

    14 t = 1/2 x 9.8 t²

    t = 28 / 9.8

    t = 2.85 s.
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