1000 kg elevator accelerates upward at 1.0 m/s 2 for 10 m, starting from rest.

a. how much work does gravity do on the elevator?

b. how much work does the tension in the elevator cable do on the elevator?

c. use the work-kinetic energy theorem to find the kinetic energy of the elevator as it reaches 10 m.

d. what is the speed of the elevator as it reaches 10 m?

a. The work that is done by gravity on the elevator is:

Work = force * distance

= mass * gravity * distance

= 1000 * 9.81 * 10

= 98,100 J

b. The work that is done by the tension in the elevator cable do on the elevator is

Work = force * distance

= mass * acceleration * 11

= 1000 * (9.81 + 1) * 10

= 108,100 J

c. PE at 10m = 1000 * 9.81 * 10 = 98,100 J

Work done by cable = PE + KE

108,100 J = KE + 98,100 J

KE = 10,000 J

d. The speed can be calculated using the KE value

KE = 0.5 m v^2

10,000 J = 0.5 * 1000 kg * v^2

v = 4.47 m/s