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24 May, 16:17

If you were to drop a rock from a tall building, assuming that it had not yet hit the ground, and neglecting air resistance. What is its vertical displacement (in m) after 10 s? (g = 10 m/s2)

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  1. 24 May, 16:27
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    500m

    Explanation:

    Using the equation of motion S = ut + 1/2 gt²

    S = the vertical displacement (in m)

    u = initial velocity of the object (in m/s)

    g = acceleration due to gravity (in m/s²)

    t = time taken (in secs)

    Given u = 0m/s, g = 10m/s² and t = 10s, substituting this value into the equation to get the vertical displacement w have;

    S = 0+1/2 (10) (10) ²

    S = 1000/2

    S = 500m

    The vertical displacement after 10seconds is 500m
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