The force required to compress a non-standard spring as a function of displacement from equilibrium x is given by the equation f (x) = ax2 - bx, where a = 65 n/m2, b = 12 n/m, and the positive x direction is in the compression direction of the spring.

Question

Roselyn Reynolds

Physics

14 May, 07:09

The force required to compress a non-standard spring as a function of displacement from equilibrium x is given by the equation f (x) = ax2 - bx, where a = 65 n/m2, b = 12 n/m, and the positive x direction is in the compression direction of the spring.

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Tanner Noble · Answer 1

Answer: F (x) = ax^2 - bx or F (x) = axÂ˛ - bx F (x) = 30xÂ˛ - 6x â"F (x) dx = â" (30xÂ˛ - 6x) dx as this is evaluated from zero to x W = 10xÂł - 3xÂ˛ <===ANS W = 10 (0.42Âł) - 3 (0.42Â˛) - [10 (0Âł) - 3 (0Â˛) ] W = 0.212 J <===ANS W = 10 (0.72Âł) - 3 (0.72Â˛) - [10 (0.42Âł) - 3 (0.42Â˛) ] W = 1.966 J <===ANS