Ask Question
23 December, 00:02

A large rectangular tub is filled to a depth of 2.60 m with olive oil, which has density 915 kg/m3. If the tub has length 5.00 m and width 3.00 m, calculate (a) the weight of the olive oil, (b) the force of air pressure on the sur - face of the oil, and (c) the pressure exerted upward by the bottom of the tub.

+4
Answers (1)
  1. 23 December, 00:15
    0
    weight is 3.50 x 10^5 N

    force is 1.52 * 10^6 N

    pressure is 1.25 * 10^5 Pa

    Explanation:

    given data

    Given data

    depth = 2.60 m

    density = 915 kg/m3

    length = 5.00 m

    width = 3.00 m

    to find out

    weight of the olive oil, force of air pressure and the pressure exerted upward

    solution

    we know density = mass / volume

    mass = density * width * length * depth

    mass = (915) (3) (5) (2.60)

    mass = 3.57 x 10^4 Kg

    so weight = mg = 3.57 x 10^4 (9.81) = 3.50 x 10^5 N

    weight is 3.50 x 10^5 N

    and

    we know force = pressure * area

    area = 3 * 5 = 15 m²

    and we know atmospheric Pressure is about 1.01 * 10^5 Pa

    so force = 1.01 * 10^5 (15) = 1.52 x 10^6 N

    force is 1.52 * 10^6 N

    and

    we know Fup - Fdown = Weight

    so

    Fup = 1.52 * 10^6 + 3.50 * 10^5

    Fup = 1.87 * 10^6 N

    so pressure = Fup / area

    pressure = 1.87 * 10^6 / 15

    pressure is 1.25 * 10^5 Pa
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A large rectangular tub is filled to a depth of 2.60 m with olive oil, which has density 915 kg/m3. If the tub has length 5.00 m and width ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers