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8 June, 06:13

What is the length of a box in which the minimum energy of an electron is 1.5*10^-18 J?

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  1. 8 June, 06:26
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    L=2*10^-10m

    Explanation:

    we need to evaluate for a minimum energy:

    Planck constant = h = 6,62607015 * 10 - 34 kg⋅m2⋅s-1

    1.5*10^-18J = 10eV

    En = n^2h^2 / 8mL^2

    for n=1 (minimum energy)

    E1 = h^2 / 8mL^2

    so ...

    L^2 = h^2 / (8mE1)

    L^2 = (6.63*10^-34) ^2 / [ 8 (9.11*10^-31) * (1.5*10^-18J) ]

    L^2 = 4.02*10^-20

    L = 2*10^-10 m
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