A man runs with a speed of 6 m/s off a platform that is 10

mabove the water. How fast is he moving when he hits thewater?

Ignore air resistance ...

Answer:15.2m/s

Explanation: Solution

Initial velocity (u) = 6 meters per second

Final velocity (v) = ?

Gravitational force (g) = 9.8meter per second (square)

Height=10meters

Formula=

V (square) = u (square) + 2*g (m/s (square) * height (m)

Velocity = √6 (square) + √ 2*9.8*10

Velocity = √6*6+√2*9.8*10

Velocity = √36+√196

Velocity=√232

Velocity=15.2m/s.

This means that the man will be running at 15.2meters per second at the time he hits the ground. His final speed was increased because of the impact of the force of gravity (g).