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20 August, 13:31

A child of mass 48.7 kg sits on the edge of a merry-go-round with radius 3 m and moment of inertia 376.938 kg m^2. The merry-go-round rotates with an angular velocity of 2.5 rad/s. What radial force does the child have to exert to stay on the merry-go-round? Answer in units of N.

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  1. 20 August, 13:58
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    913.125 N

    Explanation:

    From the question,

    Applying

    Fc = mω²r ... Equation 1

    Where Fc = radial force of the child, m = mass of the child, ω = angular velocity, r = radius of the merry go round.

    Given: m = 48.7 kg, ω = 2.5 rad/s, r = 3 m

    Substitute into equation 1

    Fc = 48.7 (2.5²) (3)

    Fc = 48.7*6.25*3

    Fc = 913.125 N

    Hence the radial force the child have to exert to stay on the merry-go-round = 913.125 N
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