Ask Question
24 November, 22:04

How much energy can be stored in a spring with k = 470 n/m if the maximum possible stretch is 17.0 cm?

+1
Answers (1)
  1. 24 November, 22:06
    0
    The strain energy stored in a linear spring is

    SE = (1/2) * k*x²

    where

    k = the spring constant

    x = the extension (or compression) of the spring

    Given:

    k = 470 N/m

    x = 17.0 cm = 0.17 m

    Therefore

    SE = 0.5 * (470 N/m) * (0.17 m) ² = 6.7915 J

    Answer: 6.8 J (nearest tenth)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “How much energy can be stored in a spring with k = 470 n/m if the maximum possible stretch is 17.0 cm? ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers