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9 March, 02:57

2. A ball tied to a pole by a rope swings in a circular path with a centripetal acceleration of 2.7 m/s. If the ball has a

tangential speed of 2.0 m/s, what is the diameter of the circular path in which it travels?

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Answers (2)
  1. 9 March, 03:00
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    2.96m
  2. 9 March, 03:19
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    Answer: The diameter of the circular path is 2.96m

    Explanation: centripetal acceleration = tangential speed^2 / radius of the circular path.

    Centripetal acceleration = 2.7m/s^2

    Tangential speed = 2.0m/s

    Radius = 2.0^2 / 2.7 = 4/2.7

    = 1.48m

    Diameter = radius*2

    = 1.48*2 = 2.96m.
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