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28 May, 11:04

An object accelerates from rest, with a constant acceleration of 6.4 m/s^2, what will its velocity be after 7s?

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Answers (2)
  1. 28 May, 11:17
    0
    Using the first kinematic equation,

    v (final) = v (inital) + at

    v (final) = 0 + (6.4 m/s^2) (7 s)

    v (final) = 44.8 m/s
  2. 28 May, 11:24
    0
    A = v/t

    hence v = at

    = 6.4 * 7
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