A platinum sphere with radius 0.0199 m is totally immersed in mercury. Find the weight of the sphere, the buoyant force acting on the sphere, and the sphere's apparent weight. The densities of platinum and mercury are 2.14104 kg/m3 and 1.36104 kg/m3, respectively.

Question

Erica Mccarty

Physics

11 November, 00:01

A platinum sphere with radius 0.0199 m is totally immersed in mercury. Find the weight of the sphere, the buoyant force acting on the sphere, and the sphere's apparent weight. The densities of platinum and mercury are 2.14104 kg/m3 and 1.36104 kg/m3, respectively.

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Answers (1)

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Haven Gallegos · Answer 1

Weight = 6.919 n

Buoyant force = 4.397 N

Apparent weight = 2.522 N

Explanation:

radius, r = 0.0199 m

density of platinum = 2.14 x 1064 kg/m^3

density of mercury = 1.36 x 1064 kg/m^3

Weight of sphere = volume of sphere x density of platinum x g

= 4/3 x 3.14 x (0.0199) ^3 x 2.14 x 10^4 x 9.8 = 6.919 N

Buoyant force acting on sphere = Volume of sphere x density of mercury x g

= 4/3 x 3.14 x (0.0199) ^3 x 1.36 x 10^4 x 9.8 = 4.397 N

Apparent weight = True weight - Buoyant force = 6.919 - 4.397 = 2.522 N

A platinum sphere with radius 0.0199 m is totally immersed in mercury. Find the weight of the sphere, the buoyant force acting on the sphere, and the sphere's apparent weight. The densities of platinum and mercury are 2.14*104 kg/m3 and 1.36*104 kg/m3, respectively.

A platinum sphere with radius 0.0199 m is totally immersed in mercury. Find the weight of the sphere, the buoyant force acting on the sphere, and the sphere's apparent weight. The densities of platinum and mercury are 2.14104 kg/m3 and 1.36104 kg/m3, respectively.