the velocity of a car increaaes from 43.2 km/h [N] to 86.4 km/h [N] over a 3 second interval. what is the cars acceleration in m/s?

V0 = 43.2 km/h

Vf = 86.4 km/h

t0 = 0s

tf = 3s

The law of acceleration is a = vf-v0/t0-tf

First, we need to convert the velocity to m/s, so after converted: v0 = 12 m/s, and vf = 24m/s.

Now we can solve it by using the law:

a = 24-12/3-0 = 12/3 = 4m/s^2

Sol. Initial velocity u = 43.2 km/hr = 12 m/s u = 12 m/s, v = 0 a = - 6 m/s2 (deceleration) Distance S = (V^2-u^2) / (2 (-6)) = 12 m