A runner starts from rest and accelerates uniformly to a speed of 8.0 meters per

second in 4.0 seconds. The magnitude of the acceleration of the runner is

O

32 m/s/s

o

9.8 m/s/s

O

2.0 m/s/s

O 0.50 m/s/s

Magnitude of acceleration is 2 m/s²

Explanation:

Here, the speed or velocity of the runner = 8 m/s and time = 4 s. Using these values, the magnitude of the acceleration has to be found. Acceleration is given by a = velocity/time

⇒ Acceleration = 8/4 = 2 m/s²

So the magnitude of acceleration is 2 m/s²

2m/s2

Explanation:

a = v - u / t

Since the runner starts from rest, initial velocity u is Zero

Final velocity v = 8.0m/s

Time = 4.0secs

a = 8.0 - 0 / 4.0

a = 8.0/4.0

a = 2m/s2