Ask Question
27 May, 13:51

A water drop of mass 20g falls to the ground with a velocity of 8m/s from a height of 20m. what is the air resistance force acting on the water drop?

+4
Answers (1)
  1. 27 May, 14:19
    0
    0.164 N

    Explanation:

    Newton's second law: sum of the forces equals mass times acceleration.

    ∑F = ma

    F - mg = ma

    a = (F - mg) / m

    In real life, air resistance is a function of velocity. But we will assume that it is constant.

    Given:

    y₀ = 20 m

    y = 0 m

    v₀ = 0 m/s

    v = - 8 m/s

    Find: a

    v² = v₀² + 2a (y - y₀)

    (-8 m/s) ² = (0 m/s) ² + 2a (0 m - 20 m)

    a = - 1.6 m/s²

    Therefore:

    -1.6 m/s² = (F - 0.020 kg * 9.8 m/s²) / 0.020 kg

    F = 0.164 N

    Round as needed.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A water drop of mass 20g falls to the ground with a velocity of 8m/s from a height of 20m. what is the air resistance force acting on the ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers