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31 July, 01:23

A 6 N force and a 15 N force act on an object. The moment arm of the 6 N force is 0.4 m. If the 15 N 20. force provides 5 times the torque of the 6 N force, what is its moment arm?

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  1. 31 July, 01:45
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    0.8 m

    Explanation:

    For "6 N" force:

    F = magnitude of the force = 6 N

    r = moment arm = 0.4 m

    Torque due to "6 N" force is given as

    τ = r F

    τ = (0.4) (6)

    τ = 2.4 Nm

    For " 15 N" force:

    F' = magnitude of the force = 15 N

    r' = moment arm = ?

    τ' = Torque = 5 τ = 5 x 2.4 = 12 Nm

    Torque due to "15 N" force is given as

    τ' = r' F'

    12 = r' (15)

    r' = 0.8 m

    So the moment arm for "15 N" force is 0.8 m
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