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30 August, 09:19

A 10-N force is exerted on a box, moving it 20 m in the same direction. What is the magnitude of work done on the box?

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  1. 30 August, 09:38
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    F = 10 N

    d = 20 m

    θ = 0°

    W = F (dot product) D = F * D * cos (angle between them)

    W = FDcosθ

    W = 10 * 20 * cos0 = 200 J
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