A 2.41 kg block is pushed 1.42 m up a vertical wall with constant speed by a constant force of magnitude f applied at an angle of 59.9 ◦ with the horizontal. the acceleration of gravity is 9.8 m/s 2. 2.41 kg 59 f. 9 ◦ if the coefficient of kinetic friction between the block and wall is 0.521, find the work done by f.

Question

Aylin Case

Physics

18 August, 14:07

A 2.41 kg block is pushed 1.42 m up a vertical wall with constant speed by a constant force of magnitude f applied at an angle of 59.9 ◦ with the horizontal. the acceleration of gravity is 9.8 m/s 2. 2.41 kg 59 f. 9 ◦ if the coefficient of kinetic friction between the block and wall is 0.521, find the work done by f.

+1

Answers (1)

Know the Answer?

Jairo Smith · Answer 1

Refer to the diagram shown below.

The weight of the block is

W = (2.41 kg) * (9.8 m/s²) = 23.618 N

The kinetic coefficient of friction is

μ = 0.521

The normal reaction is

N = f cos (59.9°) = 0.5015f N

The frictional resistive force is

R = μN = 0.521 * (0.5015f N) = 0.2613f N

For dynamic force balance,

f sin (59.9°) = W + R

0.8652f = 23.618 + 0.2613f

0.6039f = 23.618

f = 39.109 N

The block moves by 1.42 m.

The work done is

W = (f sin (59.9° N) * (1.42 m)

= 39.109*sin (59.9°) * 1.42

= 48.05 J

Answer: 48.0 J (nearest tenth