A 10 kg box, sliding to the right across a rough horizontal floor, accelerates at - 2 m/s^2 due to the force of friction. Calculate the coefficient of kinetic friction between the box and the floor and the magnitude of the net force acting on the box.

Question

Maggie Leach

Physics

11 October, 13:45

A 10 kg box, sliding to the right across a rough horizontal floor, accelerates at - 2 m/s^2 due to the force of friction. Calculate the coefficient of kinetic friction between the box and the floor and the magnitude of the net force acting on the box.

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Mckinley Horton · Answer 1

According to Newton's second law of motion, Fnet = m x a. From the given above,

Fnet = (10 kg) x (-2 m/s²) = - 20 N

The force of friction, Ff, which is a negative force is the product of the normal force and the coefficient of friction,

Ff = 20 N = k x (10 kg x 9.8 m/s²)

The value of k from the equation is 0.204. Thus, the coefficient of friction is equal to 0.204.