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Krish White
Physics
9 October, 07:30
How do you solve this If y=10^; then x=
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Kiki
9 October, 07:35
0
Apply logs to both sides
logy=log10^x
log y = x log10
log y = x (1)
x = log y / 1
x = log y
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Donavan Robertson
9 October, 07:49
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This equation isn't complete but if you are doing something that involves having y=10^whatever x is, then you just solve it like you would a normal equation, and then boom you have x and y.
This equation isn't complete ...
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