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Today, 12:03

An LC circuit has a 6.00 mH inductor. The current has its maximum value of 0.570 A at t = 0s. A short time later the capacitor reaches its maximum potential difference of 66.0 V. What is the value of the capacitance?

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  1. Today, 12:18
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    C = 44.75 x 10⁻⁸ F

    Explanation:

    Assuming no loss of energy between capacitor and inductor

    energy in inductor initially = 1/2 Li₀² where L is inductance and i₀ is peak current.

    =.5 x 6 x 10⁻³ x. 57²

    =.97 x 10⁻³ J.

    This energy is transferred to capacitor.

    energy of capacitor = 1/2 CV²

    =.5 x C x 66²

    = 2178 C

    2178C =.97 x 10⁻³

    C = 44.75 x 10⁻⁸ F.
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