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1 May, 18:29

If a 10kg block is at rest on a table and a 1200N force is applied in the eastward direction for 10 seconds, what is the acceleration on the block?

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  1. 1 May, 18:58
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    a = 120 m/s²

    Explanation:

    We apply Newton's second law in the x direction:

    ∑Fₓ = m*a Formula (1)

    Known data

    Where:

    ∑Fₓ: Algebraic sum of forces in the x direction

    F: Force in Newtons (N)

    m: mass (kg)

    a: acceleration of the block (m/s²)

    F = 1200N

    m = 10 kg

    Problem development

    We replace the known data in formula (1)

    1200 = 10*a

    a = 1200/10

    a = 120 m/s²
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