He density of copper is 8.96g/cm^3 and the density of water is 1 g/cm^3. When a copper is submerged in a cylindrical beaker whose bottom has surface area 10 cm^2 the water level rises by 2 cm. The volume of the cylinder is the area of its base times its height. a) What is the specific gravity of copper?

b) What is the buoyant force on the copper object?

c) What is the buoyant force on the copper object?

d) What is the mass of the copper object?

(a) 8.96

(b) 19600 dyne

(c) 19600 dyne

(d) 20 g

Explanation:

dcu = 8.96 g/cm^3, dw = 1 g/cm^3, A = 10 cm^2

Water level rises by 2 cm.

(a) The specific gravity of copper = density of copper / density of water

8.96 / 1 = 8.96

(b) According to the Archimedes's principle, the buoyant force acting on the body is equal to the weight of liquid displaced by the body.

Weight of water displaced by the copper = Area of beaker x rise in water level

x density of water x gravity

= 10 x 2 x 1 x 980 = 19600 dyne

(c) Same as part b

(d) Let mass of copper be m.

For the equilibrium condition,

the true weight of copper = Buoyant force acting on copper

m x g = 19600

m = 19600 / 980 = 20 g