A ring of mass 32 kg has an angular velocity of 110 rad/s. The radius of the ring is 0.380 m. What is the rotational kinetic energy of the ring?

Question

Fatima Huynh

Physics

23 November, 20:43

A ring of mass 32 kg has an angular velocity of 110 rad/s. The radius of the ring is 0.380 m. What is the rotational kinetic energy of the ring?

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Answers (1)

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Thaddeus Kennedy · Answer 1

Answer: 2.8 kJ

Explanation: Given that

The mass M = 32 kg

w = 110 rad/s

r = 0.380 m

Rotational kinetic energy = 1/2 Iw^2

Where I = moment of inertia

I = Σ mr^2

I = 32 * 0.38^2

I = 4.6208

Rotational K. E = 1/2 * 4.6208 * 110^2

Rotational K. E = 27955.84 J

= 2.8 KJ approximately