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12 September, 08:42

A bicyclist in the Tour de France crests a mountain pass as he moves at 18 km/h. At the bottom, 3.8 km farther, his speed is 85 km/h. What was his average acceleration (in m/s2) while riding down the mountain?

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  1. 12 September, 09:11
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    Initial speed, u = 18 km/h

    Final speed, v = 85 km,/h

    Distance traveled, s = 3.8 km

    Note:

    1 km/h = 0.27778 m/s

    Therefore

    u = 18*0.27778 = 5 m/s

    v = 85*0.27778 = 23.61 m/s

    s = 3.8 km = 3800 m

    Let a = the acceleration.

    Use the formula

    v² = u² + 2as, or

    a = (v² - u²) / 2s

    = (557.493 - 25) / 7600

    = 0.07 m/s²

    Answer: 0.07 m/s²
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