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9 October, 20:40

Two 8.0 Ω lightbulbs are connected in a 12 V series circuit. What is the power of both glowing bulbs?

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  1. 9 October, 20:48
    0
    18 W

    Explanation:

    Applying,

    P = V²/R ... Equation 1

    Where P = Power of both glowing bulbs, V = Voltage, R = Combined Resistance of both bulbs

    Since: It is a series circuit,

    Then,

    R = R1+R2 ... Equation 2

    Where R1 = Resistance of the first bulb, R2 = Resistance of the second bulb

    Given: R1 = R2 = 8 Ω

    Substitute into equation 1

    R = 8+8

    R = 16 Ω

    Also Given: V = 12 V

    Substitute into equation 1

    P = 12²/8

    P = 144/8

    P = 18 W
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