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25 April, 23:14

At the moment car a is starting from rest and accelerating at 5.0 m/s2, car b passes it moving at a constant speed of 45m/s. how long will it take car a to catch up with car b?

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  1. 25 April, 23:27
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    X=v (initial) t+.5 (a) t^2. Car B's displacement can be represented by equation x=45t. Car A can be represented by the equation x=.5 (5) t^2. Plug these equations into a graphing calc and find intercept, the x value is time, the y is displacement.
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