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12 December, 14:34

How long must a current of 100ma flow so as to transfer a charge of 80c

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  1. 12 December, 14:51
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    800 s

    Explanation:

    This can be solved using the equation:

    I = Q/T where

    I is the amount of current in A

    Q is the amount of charge in C

    T is the duration in s.

    Hence by substituting the values, we get:

    100 * 10^-3 = 80/T

    T = 80 / 100 * 10^-3

    T = 800 s

    (Note: When substituting I, remember to change from mA to A)
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