Ask Question
21 August, 13:51

A 34.34 g sample of a substance is initially at 26.7 °C. After absorbing 2205 J of heat, the temperature of the substance is 152.1 °C. What is the specific heat (c) of the substance?

+3
Answers (1)
  1. 21 August, 14:16
    0
    The specific heat of the substance is c = 512.04 J/kg K

    Explanation:

    ΔQ = 2205 J

    m = 0.03434 kg

    ΔT = 125.4 ºC

    ΔQ = m * c * ΔT

    c = ΔQ / (m * ΔT)

    c = 512.04 J/Kg K
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A 34.34 g sample of a substance is initially at 26.7 °C. After absorbing 2205 J of heat, the temperature of the substance is 152.1 °C. What ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers