Ask Question
24 September, 01:04

The period of a simple pendulum in a grandfather clock on another planet is 1.80 s. What is the acceleration due to gravity (in m/s2) on this planet if the length of the pendulum is 1.00?

+3
Answers (1)
  1. 24 September, 01:16
    0
    12.17 m/s²

    Explanation:

    The formula of period of a simple pendulum is given as,

    T = 2π√ (L/g) ... Equation 1

    Where T = period of the simple pendulum, L = length of the simple pendulum, g = acceleration due to gravity of the planet. π = pie

    making g the subject of the equation,

    g = 4π²L/T² ... Equation 2

    Given: T = 1.8 s, l = 1.00 m

    Constant: π = 3.14

    Substitute into equation 2

    g = (4*3.14²*1) / 1.8²

    g = 12.17 m/s²

    Hence the acceleration due to gravity of the planet = 12.17 m/s²
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The period of a simple pendulum in a grandfather clock on another planet is 1.80 s. What is the acceleration due to gravity (in m/s2) on ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers