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12 February, 21:46

An electric field of intensity 3.80 kN/C is applied along the x-axis. Calculate the electric flux through a rectangular plane 0.350 m wide and 0.700 m long if the following conditions are true.

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  1. 12 February, 21:52
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    Answer: 1.55 x 10⁴ Nm²c^-1

    Explanation: The electric flux, electric field intensity and area are related by the formulae below.

    Φ = EAcosθ,

    Where Φ = electric flux (Nm²c^-1)

    E = electric field intensity (N/m²)

    A = Area (m²)

    θ = this is angle between the planar area and the magnetic flux

    For our question E=3.80KN/c = 3800 N/c

    A = 0.700 x 0.350 = 0.245m²

    θ = 0° (this is because the electric field was applied along the x axis, thus the electric flux will be parallel to the area).

    Hence Φ = 3800 x 0.245 x cos (0)

    = 3800 x 0.245 x 1 (value of cos 0° = 1)

    = 1.55 x 10⁴ Nm²c^-1

    Thus the electric field is 1.55 x 10⁴ Nm²c^-1
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