A 0.25 kg baseball is in contact with a bat for 0.0075 s and exerts a force of 18,500 N. What impulse is delivered to the ball?

The answer is 138.75 kgm/s

Impulse (I) is the multiplication of force (F) and time interval (Δt) : I = F · Δt

It is given:

m = 0.25

F = 18,500 N = 18,500 kgm/s²

Δt = 0.0075 s

I = ?

I = F · Δt = 18,500 5kgm/s² * 0.0075 s = 18,500 * 0.0075 kgm/s² * s = 138.75 kgm/s

The other answer is correct, but when on the site is asks for that answer rounded so it would be 140.