A force is applied with a magnitude of 70 N at an angle of 50 degrees from the horizontal. What are the horizontal and vertical components of force?

Fy = 53.62 N

Fx ≈ 50 N

Explanation:

let Fx be the horizontal component of the applied force and Fy be the vertical component of the applied force then:

Fy = F*sin (∅)

= (70) * sin (50°)

= 53.62 N

Fx = F*cos (∅)

= (70) * cos (50°)

≈ 50 N