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9 January, 20:25

A force is applied with a magnitude of 70 N at an angle of 50 degrees from the horizontal. What are the horizontal and vertical components of force?

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  1. 9 January, 20:27
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    Fy = 53.62 N

    Fx ≈ 50 N

    Explanation:

    let Fx be the horizontal component of the applied force and Fy be the vertical component of the applied force then:

    Fy = F*sin (∅)

    = (70) * sin (50°)

    = 53.62 N

    Fx = F*cos (∅)

    = (70) * cos (50°)

    ≈ 50 N
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