A container of gas is at a pressure of 3.7 * 105 Pa How much work is done by the gas if its volume expands by 1.6 m3?

Work is done by the gas = 5.92 x 10⁵ J = 592 kJ

Explanation:

Work done at fixed pressure, W = PΔV

Pressure, P = 3.7 x 10⁵ Pa

Change in volume, ΔV = 1.6 m³

Substituting the values of pressure and change in volume we will get

Work done at fixed pressure, W = PΔV = 3.7 x 10⁵ x 1.6 = 5.92 x 10⁵ J

Work is done by the gas = 5.92 x 10⁵ J = 592 kJ