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26 January, 20:30

The strength of the Earth's magnetic field B at the equator is approximately equal to 5 * 10-5 T. The force on a charge q moving in a direction perpendicular to a magnetic field is given by F = q v B, where v is the speed of the particle. The direction of the force is given by the right-hand rule. Suppose you rub a balloon in your hair and your head acquires a static charge of 4 * 10-9 C. If you are at the equator and driving west at a speed of 60 m/s, what is the strength of the magnetic force on your head due to the Earth's magnetic field? Answer in units of N

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  1. 26 January, 20:53
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    1.2 x 10⁻¹¹ N

    Explanation:

    B = magnitude of magnetic field at the equator = 5 x 10⁻⁵ T

    q = magnitude of charge acquired by the head = 4 x 10⁻⁹ C

    v = speed of driving at the equator = 60 m/s

    Magnitude of magnetic force on the head at the equator is given as

    F = q v B

    Inserting the above values in the equation

    F = (4 x 10⁻⁹) (60) (5 x 10⁻⁵)

    F = 1.2 x 10⁻¹¹ N
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