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23 October, 12:58

You are moving into an apartment and take the elevator to the 6th floor. Suppose your weight is 660 N and that of your belongings is 1100 N. (a) Determine the work done by the elevator in lifting you and your belongings up to the 6th floor (15.2 m) at a constant velocity. (b) How much work does the elevator do on you alone (without belongings) on the downward trip, which is also made at a constant velocity

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  1. 23 October, 13:07
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    Total weight

    My weight+weight of belongings

    660+1100=1760N.

    a. Work done by the elevator to travel a total height of 15.2m

    Using newton law of motion

    ΣF = ma

    There are only two forces acting upward, the weight and the reaction by the elevator

    Also note it is moving at constant velocity then, a=0

    N - W=0

    Then, N=W

    N=1760N

    So, workdone is given as

    Wordone, = force * distance

    Work done=1760*15.2

    W=26,752J

    W=26.752KJ

    b. Work done on me alone is still need to go through the same process but will remove the weight of the belonging

    Therefore,

    Weight now = 660N

    And using the same equation of motion

    ΣF = ma

    Comstant velocity, a=0

    N - W=0

    N=W

    N=660N

    Then, workdone

    W=F*d

    W=660*15.2

    W=10,032J

    W=10.032KJ
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