A technician connects one lead of a digital voltmeter to the positive () terminal of the battery and the other meter lead to the battery terminal (B) of the starter solenoid and then cranks the engine. During cranking, the voltmeter displays a reading of 878 millivolts. Technician A says that this reading indicates that the positive battery cable has too high resistance. Technician B says that this reading indicates that the starter is defective. Which technician is correct

A. Technician B only

B. Technician A only

C. Both Technician A and Technician B

D. Neither Technician A nor Technician B

Question

Emma Wilkerson

Physics

17 August, 22:01

A technician connects one lead of a digital voltmeter to the positive () terminal of the battery and the other meter lead to the battery terminal (B) of the starter solenoid and then cranks the engine. During cranking, the voltmeter displays a reading of 878 millivolts. Technician A says that this reading indicates that the positive battery cable has too high resistance. Technician B says that this reading indicates that the starter is defective. Which technician is correct

A. Technician B only

B. Technician A only

C. Both Technician A and Technician B

D. Neither Technician A nor Technician B

+1

Answers (1)

Know the Answer?

Alfred Barrera · Answer 1

Technician A only

Explanation:

The true resistance of a circuit is shown by voltage drop since high voltage drop indicates high resistance while low voltage drop shows low resistance of a circuit. For our case in the question, the voltage drop should not exceed 200 millivolts during cranking but we realize a reading of 878 millivolts in the voltmeter, a clear indicator of high resistance. This implies that the positive battery cable has too high resistance but not a sign of defect in the system. Therefore, technician A is correct.