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18 March, 18:36

Sr-90 has a half-life of T1/2 = 2.85 a (years). How much Sr-90 will remain in a 5.00 g sample after 5.00 a? Show all of your work. (2 marks)

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  1. 18 March, 18:39
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    1.48 g

    Explanation:

    A = A₀ (½) ^ (t / T)

    where A is the final amount,

    A₀ is the initial amount,

    t is time,

    and T is the half life.

    A = (5.00 g) (½) ^ (5.00 a / 2.85 a)

    A = 1.48 g
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