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27 October, 16:03

A 45.0 kg ice skater needs a 25 N horizontal force to get moving on a smooth ice surface. What is the coefficient of friction between the ice and the skates?

a. 1.80

c. 0.18

b. 0.057

d. 0.56

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Answers (1)
  1. 27 October, 16:25
    0
    As we know f=k/N

    k = f / N

    So

    N = m * g = putting values 45 kg * 9.81 m/s² = 441.45 N

    k = 25 N : 441.45 N =

    so the coeffcient of friction between the ice and the skates is 0.057
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