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21 December, 06:40

Suppose a clay model of a koala bear has a mass of 0.25 kg and slides on ice at a speed of 0.85 m/s. It runs into another clay model, which is initially motionless and has a mass of 0.45 kg. Both being soft clay, they naturally stick together. Friction on ice can be neglected.

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  1. 21 December, 07:09
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    vf = 0.3 m/s

    Explanation:

    Assuming no external forces act during the collision, total momentum must be conserved.

    The initial momentum is due to the koala bear moving at 0.85 m/s:

    p₀ = m₁ * v₀₁ = 0.25 kg. 0.85 m/s = 0.21 N. m

    As the collision is inelastic, both masses stick together, so the final momentum can be written as follows:

    p₁ = (m₁ + m₂) * vf₁₂ = 0.7 kg * vf₁₂ = 0.21 N. m (as p₀ = p₁,

    Now, we can solve for the common speed of both masses after the collision, as follows:

    vf₁₂ = 0.21 N. m / 0.7 kg = 0.3 m/s (in the same direction that v₀₁).
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