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5 January, 08:06

The electric field in a particular thundercloud is 3.8 x 105 N/C. What is the acceleration (in m/s2) of an electron in this field? (Enter the magnitude.) m/s2

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  1. 5 January, 08:11
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    6.68 x 10^16 m/s^2

    Explanation:

    Electric field, E = 3.8 x 10^5 N/C

    charge of electron, q = 1.6 x 10^-19 C

    mass of electron, m = 9.1 x 10^-31 kg

    Let a be the acceleration of the electron.

    The force due to electric field on electron is

    F = q E

    where q be the charge of electron and E be the electric field

    F = 1.6 x 10^-19 x 3.8 x 10^5

    F = 6.08 x 10^-14 N

    According to Newton's second law

    Force = mass x acceleration

    6.08 x 10^-14 = 9.1 x 10^-31 x a

    a = 6.68 x 10^16 m/s^2
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