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13 April, 19:21

At a constant pressure at a temperature of 280 k the gas in the cylinder has the volume of 10 liters if the volume of the gas is increased to 20 liters what is the new temperature

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  1. 13 April, 19:30
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  2. 13 April, 19:45
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    Since there is constant pressure, you can use Charles's Law:

    V1/T1 = V2/T2

    10L/280K = 20L/T

    0.0357 = 20 / T

    T = 20/0.0357

    T = 560K which is the new temperature
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