A transverse wave is traveling through a canal. If the distance between two successive crests is 3.17 m and four crests of the wave pass a buoy along the direction of travel every 22.6 s, determine the following.

(a) frequency of the wave

1 Hz

(b) speed at which the wave is traveling through the canal

2 m/s

a. 0.18Hz

b. 0.56m/s

Explanation:

From the question we can deduct the following parameters

The wavelength, λ is define as the distance between two successful crest or trough and from the question we conclude that wavelength is 3.17m.

Also the period of the wave T can be computed as

T=22.6/4

T=5.65secs.

a. To compute the frequency, recall that frequency, F=1/period.

Hence,

F=1/5.65

F=0.18Hz

b. Next we compute the wave speed.

Wave speed=frequency * wavelength

Wave speed = 0.18*3.17

Wave speed = 0.56m/s