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22 October, 00:00

A 140 g ball at the end of a string is revolving uniformly in a horizontal circle of radius 0.537 m. The ball makes 2.27 revolutions in a second. What is its centripetal acceleration?

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  1. 22 October, 00:02
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    109.13 rad/s^2

    Explanation:

    m = 140 g = 1.4 kg, r = 0.537 m, f = 2.27 rps

    The centripetal acceleration is given by

    a = r ω^2

    a = r x (2 π f) ^2

    a = 0.537 x (2 x 3.14 x 2.27) ^2

    a = 109.13 rad/s^2
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