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27 October, 10:01

how much energy is stored in a 7.0 cm spring that has a spring constant of 500 N/m when it is stretched 3.0 cm

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  1. 27 October, 10:15
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    12250 J

    Explanation:

    elastic potential energy = 0.5 * spring constant * (extension) 2

    spring constant = 500

    extension = 7cm

    7^2=49

    0.5 * 500 * 49 = 12250 J or 12.25kJ
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