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2 March, 07:58

An unknown material has a mass

of 5.61 kg, and its temperature

increases by 0.124°C when

1320 J of heat are added. What is

the specific heat of the material?

(Unit = J / (kg*C))

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Answers (2)
  1. 2 March, 08:01
    0
    1897.53J/Kg°C

    Explanation:

    Data obtained from the question include:

    M (mass of material) = 5.61 kg

    ΔT (change in temperature) = 0.124°C

    Q (heat) = 1320 J

    C (specific heat capacity of the material) = ?

    Using the formula Q = MCΔT, the specific heat capacity of the material can be obtained as follow:

    Q = MCΔT

    C = Q / MΔT

    C = 1320J / (5.61 kg x 0.124°C)

    C = 1897.53J/Kg°C

    Therefore, the specific heat capacity of the material is 1897.53J/Kg°C
  2. 2 March, 08:06
    0
    Answer: 1896.55J/kg°C

    Explanation:

    The quantity of Heat Energy (Q) required to heat a material depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

    Thus, Q = MCΦ

    Since,

    Q = 1320 joules

    Mass of material = 5.61kg

    C = ? (let unknown value be Z)

    Φ = 0.124°C

    Then, Q = MCΦ

    1320J = 5.61kg x Z x 0.124°C

    1320J = 0.696kg°C x Z

    Z = (1320J / 0.696kg°C)

    Z = 1896.55 J/kg°C

    Thus, the specific heat of the material is 1896.55J/kg°C
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