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26 May, 14:19

A man, a distance d=3~/text{m}d=3 m from a target, throws a ball at an angle / theta = 70^/circθ=70 ∘ above the horizontal. If the initial speed of the ball is v=5~/text{m/s}v=5 m/s, what height hh does the ball strike the building?

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  1. 26 May, 14:38
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    The ball doesn't strike the building because it strikes the ground at d=1.62 meters.

    Explanation:

    V = 5 m/s < 70º

    Vx = 1.71 m/s

    Vy = 4.69 m/s

    h = Vy * t - g * t²/2

    clearing t for the flying time of the ball:

    t = 0.95 s

    d = Vx * t

    d = 1.62 m
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