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23 March, 09:06

A loudspeaker diaphragm is producing a sound for 4.6 s by moving back and forth in simple harmonic motion. The angular frequency of the motion is 2.57 x 104 rad/s. How many times does the diaphragm move back and forth

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  1. 23 March, 09:16
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    Number of times the diaphragm move back and forth is 5.59*10^4

    Explanation:

    Given data,

    ω=4.6 s

    we have the formula

    f=ω/2π

    The number of times the diaphragm moves back and forth in 4.6 s is

    Number of times = ft

    Number of times = ft

    = (ω/2π) t

    = (7.54*10^4 rad/sec) (4.6 s) / 2π

    Number of time=5.59*10^4

    Number of times the diaphragm move back and forth is 5.59*10^4
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