Ask Question
18 February, 22:40

From a window that is 20 m from the ground a stone with a speed of 10m / s is thrown vertically upwards. Calculate:

a) the maximum height reached and the time it takes to reach it

b) the total time that is in the air

+2
Answers (1)
  1. 18 February, 23:00
    0
    a)

    consider the motion in upward direction as positive and down direction as negative

    Y₀ = initial position of the stone = 20 m

    v₀ = initial velocity of the stone = 10 m/s

    a = acceleration = - 9.8 m/s²

    Y = final position of the stone when it reach the maximum height

    v = final velocity at the maximum height = 0 m/s

    t = time taken to reach the maximum height

    Using the equation

    v² = v₀² + 2 a (Y - Y₀)

    0² = 10² + 2 ( - 9.8) (Y - 20)

    Y = 25.1 m

    also using the equation

    v = v₀ + a t

    inserting the values

    0 = 10 + ( - 9.8) t

    t = 1.02 sec

    b)

    consider the motion in upward direction as positive and down direction as negative

    Y₀ = initial position of the stone = 20 m

    v₀ = initial velocity of the stone = 10 m/s

    a = acceleration = - 9.8 m/s²

    Y = final position of the stone when it reach the ground = 0 m

    t = time taken to reach the ground

    Using the equation

    Y = Y₀ + v₀ t + (0.5) a t²

    0 = 20 + 10 t + (0.5) ( - 9.8) t²

    t = 3.3 sec
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “From a window that is 20 m from the ground a stone with a speed of 10m / s is thrown vertically upwards. Calculate: a) the maximum height ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers